Here we are binding a GridView in Asp.Net and C#. Points Of Remember:1. Place a TextBox in all column of FooterTemplate except first column. 2. Fire GridView's SeletedIndexChanging event. 3. Place a LinkButton with CommandName Select in first column of FooterTemplate. 4. Add namespace System.Data and System.Data.SqlClient in your C# page. <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>How to Insert new row in GridView</title> </head> <body> <form id="form1" runat="server"> <div> <asp:GridView ID="GridView1" runat="server" AutoGenerateColumns="false" CellPadding="4" ForeColor="#333333" ShowFooter="True" OnSelectedIndexChanging="GridView1_SelectedIndexChanging" > <Columns> <asp:TemplateField> <FooterTemplate> <asp:LinkButton ID="LkB1" runat="server"CommandName="Select">Insert</asp:LinkButton> </FooterTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Name"> <ItemTemplate> <asp:Label ID="Label1" runat="server" Text='<%# Eval("Name") %>'></asp:Label> </ItemTemplate> <FooterTemplate> <asp:TextBox ID="txt_Name" runat="server"></asp:TextBox> </FooterTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="Branch"> <ItemTemplate> <asp:Label ID="Label2" runat="server" Text='<%# Eval("Branch")%>'></asp:Label> </ItemTemplate> <FooterTemplate> <asp:TextBox ID="txt_Branch" runat="server"></asp:TextBox> </FooterTemplate> </asp:TemplateField> <asp:TemplateField HeaderText="City"> <ItemTemplate> <asp:Label ID="Label3" runat="server" Text='<%# Eval("City") %>'></asp:Label> </ItemTemplate> <FooterTemplate> <asp:TextBox ID="txt_City" runat="server"></asp:TextBox> </FooterTemplate> </asp:TemplateField> </Columns> <HeaderStyle BackColor="#5D7B9D" Font-Bold="True" ForeColor="White" /> <RowStyle BackColor="#F7F6F3" ForeColor="#333333" /> </asp:GridView> </div> </form> </body> </html> C# Codes :using System.Data; using System.Data.SqlClient; public partial class GridView_Insertrow : System.Web.UI.Page { // sql connection SqlConnection con = new SqlConnection(@"Data Source=RAVI-PC\SQL;Initial Catalog=db_Student;Integrated Security=True"); protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { BindGridView(); } } //method for binding GridView protected void BindGridView() { DataTable dt = new DataTable(); SqlDataAdapter da = new SqlDataAdapter("Select ID, Name,Branch,City from tbl_student", con); con.Open(); da.Fill(dt); con.Close(); if (dt.Rows.Count > 0) { GridView1.DataSource = dt; GridView1.DataBind(); } } // insert new record in database protected void GridView1_SelectedIndexChanging(object sender, GridViewSelectEventArgs e) { // find values for update TextBox txtname = (TextBox)GridView1.FooterRow.FindControl("txt_Name"); TextBox txtbranch = (TextBox)GridView1.FooterRow.FindControl("txt_Branch"); TextBox txtcity = (TextBox)GridView1.FooterRow.FindControl("txt_City"); // insert values into database SqlCommand cmd = new SqlCommand("insert into tbl_student(Name, Branch, City) values('" + txtname.Text + "','" + txtbranch.Text + "','" + txtcity.Text + "')", con); con.Open(); cmd.ExecuteNonQuery(); con.Close(); BindGridView(); } } |
Monday, March 9, 2015
How to insert new row in GridView in Asp.Net.
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